#!/usr/bin/env python3

#  a
# b c
#  d
# e f
#  g

# 1   c  f  2
# 7 a c  f  3
# 4  bcd f  4
# 2 a cde g 5
# 3 a cd fg 5
# 5 ab d fg 5
# 0 abc efg 6
# 6 ab defg 6
# 9 abcd fg 6
# 8 abcdefg 7

# 1 = len(2)
# 7 = len(3)
# 4 = len(4)
# 8 = len(7)
# 3 = len(5) and len(&1)==2 and len(&4)==3
# 5 = len(5) and len(&1)==1 and len(&4)==3
# 2 = len(5) and len(&1)==1 and len(&4)==2
# 9 = len(6) and len(&1)==2 and len(&4)==4
# 0 = len(6) and len(&1)==2 and len(&4)==3
# 6 = len(6) and len(&1)==1 and len(&4)==3


lines = (x.strip() for x in open("input.txt"))
result = 0

for line in lines:
    input, output = tuple(map(lambda x: x.split(), line.split(' | ')))
    input.sort(key=len)
    numbers = {}
    numbers[1] = set(input[0])
    numbers[4] = set(input[2])
    numbers[7] = set(input[1])
    numbers[8] = set(input[9])
    for seg in input:
        vals = set(seg)
        compare = (len(seg), len(numbers[1].intersection(vals)), len(numbers[4].intersection(vals)))
        if compare == (5, 2, 3):
            numbers[3] = vals
        elif compare == (5, 1, 3):
            numbers[5] = vals
        elif compare == (5, 1, 2):
            numbers[2] = vals
        elif compare == (6, 2, 4):
            numbers[9] = vals
        elif compare == (6, 2, 3):
            numbers[0] = vals
        elif compare == (6, 1, 3):
            numbers[6] = vals

    # prepare comparison
    numbers = {''.join(sorted(v)): k for k, v in numbers.items()}
    output = (''.join(sorted(v)) for v in output)

    # substitute
    result += int(''.join(str(numbers[v]) for v in output))

    print(numbers, output)

print(result)